The Challenge

Alright, code warriors, here’s the legendary FizzBuzz test! Your mission, should you choose to accept it, is to write a program that does the following:

• Prints the numbers from 1 to 100.
• But for multiples of 3, print “Fizz” instead of the number.
• And for multiples of 5, print “Buzz” instead of the number.
• Finally, for numbers which are multiples of both 3 and 5, print “FizzBuzz”.

Sounds simple? That’s what they all say…

A Tiny Hint

Think about using the modulo operator (%). It’s your secret weapon to detect multiples!

The Solution

Behold! The FizzBuzz code in all its glory (JavaScript version):

for (let i = 1; i <= 100; i++) {
  let output = '';
  if (i % 3 === 0) {
    output += 'Fizz';
  }
  if (i % 5 === 0) {
    output += 'Buzz';
  }
  console.log(output || i);
}
            

Don't let the code fool you! It's more straightforward than it looks. We loop through numbers 1 to 100. If a number is divisible by 3, we add "Fizz" to the output. If it's divisible by 5, we add "Buzz". And if it's divisible by both, we get "FizzBuzz"! The output || i part is a clever way to print the number if it's not a multiple of 3 or 5.

Brain Check!

Here's the real test... What will the code print for the number 15? Think carefully! Drop your answer in the comments below!